Let the speed of the train be x. We know that. ⇒ Speed = Distance/Time Speed after accident = 4/5 of x = 4x/5 According to the question, The time difference in covering 20 km due to change in speed = 45 - 36 = 9 min 20/(4x/5) -(20/x) =9/60 100/4x)-20/x=9/60 ⇒ x = 33.33 km/h ∴ The original speed of the train is 33.33 Km/h.
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