Two vehicles, named as 'X' and 'Y', travel along side-by-side paths but in opposite directions. The length of vehicle 'Y' surpasses that of 'X' by 12.5%. Their speeds are recorded at 72 km/h for 'X' and 14 m/s for 'Y'. Given that it takes them 50 seconds to fully pass one another, determine the length of 'Y'.
ATQ, Speed of Vehicle 'X' = 72 × (5/18) = 20 m/s Let the length of Vehicle 'X' be '8a' metres. So, the length of Vehcile 'Y' = 1.125 × 8a = '9a' metres [(8a+9a)/(20+14)] = 50 ATQ, Or, (17a/34) = 50 Or, a = 50 × 2 = 100 So, the length of Vehicle 'Y' = 9a = 9 × 100 = 900 metres
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