Get Started with ixamBee
Start learning 50% faster. Sign in now
ATQ, Speed of Vehicle 'X' = 72 × (5/18) = 20 m/s Let the length of Vehicle 'X' be '8a' metres. So, the length of Vehcile 'Y' = 1.125 × 8a = '9a' metres [(8a+9a)/(20+14)] = 50 ATQ, Or, (17a/34) = 50 Or, a = 50 × 2 = 100 So, the length of Vehicle 'Y' = 9a = 9 × 100 = 900 metres
5, 5, 15, 75, ?, 4725
8, 24, 48, 80, ?, 168
8 13 36 123 ? 2585
250, 279, 311, 349, 396, ?
840, 2520, 630, 3150, ?, 3675
12, 24, 46, 78, 120, ?
81, 41, 42, 64.5, ?, 330
8, 58, 75, 94, 115, ?
200 ? 96 38.4 7.68 0