A man travels to his destination in 8 hours at his normal speed. If his speed decreases by (1/10) , he travels 40 km less in the same time. Determine his usual speed.
ATQ, Let the usual speed be 10x km/h. The reduced speed = (9/10) × 10x = 9x km/h Using the formula Distance = Speed × Time, 
Usual speed = 10x = 50 km/h.
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