Traveling at his normal speed, a man covers the distance to his destination in 15 hours. If he reduces his speed by (1/5) , he covers 75 km less in the same period. Find his usual speed.
ATQ, Let the usual speed be 5x km/h. The reduced speed = (4/5) × 5x = 4x km/h Using the formula Distance = Speed × Time, 
Usual speed = 5x = 25 km/h.
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