A car of length 100 meters crosses a stationary pole in 5 seconds. Another car moving at double the speed of the first car crosses a stationary truck in 6 seconds while coming from the opposite direction. Find the length of the truck.
ATQ, Speed of the first car = (100/5) = 20 m/s Speed of the second car = 2×20 = 40 m/s Relative speed when facing each other = 20+40 = 60 m/s Total distance covered by the second car in 6 seconds = 60×6 = 360 meters Length of the truck = 360−100 = 260 meters So, the length of the truck is 260 meters.
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