Question
If 'P' was 10 minutes late to the office one day, he
decided to increase his vehicle's speed by 5 km/h the next day, allowing him to arrive on time. Given that the distance from his home to his office is 130 km, what was his speed on the day he increased it?Solution
ATQ,
Let 'P's normal speed be ‘x’ km/h. Time taken to reach the office at normal speed = 130/x hour Now, after increasing the normal speed by 5 km/h. New speed = (x + 5) km/h Time taken to reach the office at new speed = 130/(x + 5) hour According to the given information, 130/x – 130/(x + 5) = 1/6 x2 + 5x – 3900 = 0 x2– 60x + 65x – 3900 = 0 x(x – 60) + 65(x – 60) = 0 (x –60)(x + 65) = 0 Therefore, x = 60 km/h Therefore, his increased speed on that day = 60 + 5 = 65 km/h
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