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ATQ,
Let 'P's normal speed be ‘x’ km/h. Time taken to reach the office at normal speed = 130/x hour Now, after increasing the normal speed by 5 km/h. New speed = (x + 5) km/h Time taken to reach the office at new speed = 130/(x + 5) hour According to the given information, 130/x – 130/(x + 5) = 1/6 x2 + 5x – 3900 = 0 x2– 60x + 65x – 3900 = 0 x(x – 60) + 65(x – 60) = 0 (x –60)(x + 65) = 0 Therefore, x = 60 km/h Therefore, his increased speed on that day = 60 + 5 = 65 km/h
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