ATQ, Let the speed of Car 'C' = '10x' km/h Distance covered by Car 'C' = 10x × 8 = '80x' km Speed of Car 'D' = 10x × 1.2 = '12x' km/h Distance covered by Car 'D' in 5 hours = 12x × 5 = '60x' km According to the question, 60x - 80x = 160 Or, 20x = 160 Or, x = 160 ÷ 20 = 8 Therefore, the speed of Car 'C' = 10x = 10 × 8 = 80 km/h
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