A thief is spotted by a policeman from 800m. When the policeman starts chasing, the thief also starts running. If the speed of the thief is 32km/h and that of the policeman is 40 km/h, then how far would the thief have run before he is overtaken?
Let, the distance covered by the thief be x km. ATQ- x/32 = (x + 0.8)/40 x/32-x/40 = 8/400 (40x-32x)/32×40 = 1/50 8x/1280 = 1/50 x =160/50 x = 3.2km Distance covered by thief = 3.2 km = 3.2 x 1000 m = 3200 m
Revel
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