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ATQ, Time taken to meet for the first time = 4000 ÷ (8 + 10) = 250 seconds So, time taken to meet for 10th time = 250 × 10 = 2500 seconds So, distance covered by 'A' in 2500 seconds = 2500 × 8 = 20000 metres And distance covered by 'B' in 2500 seconds = 2500 × 10 = 25000 metres So, required difference = 25000 - 20000 = 5000 metres
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