'A' and 'B' are running on a circular track of length 5000 metres. 'A' is running clockwise at 6 m/s while 'B' is running anti-clockwise at 8 m/s. Find the difference between the distance covered by 'A' and 'B' by the time they meet for the tenth time.
ATQ, Time taken to meet for the first time = 5000 ÷ (6 + 8) = 312.5 seconds So, time taken to meet for 10th time = 312.5 × 10 = 3125 seconds So, distance covered by 'A' in 3125 seconds = 3125 × 6 = 18750 metres And distance covered by 'B' in 3125 seconds = 3125 × 8 = 25000 metres So, required difference = 25000 - 18750 = 6250 metres
In each of the following questions you are given a figure followed by four alternatives(1), (2), (3) and (4). Choose the alternatives which is closely ...
Choose the alternatives which is closely resembles the water image of the given combination.
Question figure:
Choose the alternative which is closely resembles the water-image of the given combination.
Question figure:
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Choose the alternative which is closely resembles the water-image of the given combination.
Choose the alternatives which is closely resembles the water image of the given combination.
