ATQ, Time taken to meet for the first time = 3600 ÷ (4 + 6) = 360 seconds So, time taken to meet for 10th time = 360 × 10 = 3600 seconds So, distance covered by 'A' in 3600 seconds = 3600 × 4 = 14400 metres And distance covered by 'B' in 3600 seconds = 3600 × 6 = 21600 metres So, required difference = 21600 - 14400 = 7200 metres
I. 2y2+ 13y + 15 = 0
II. 2x2+ 11 x + 12 = 0
I. 12 x ² - 3 x – 15 = 0
II. 2 y² + ...
I. 5x² = 19x – 12
II. 5y² + 11y = 12
Roots of the quadratic equation 2x2 + x – 528 = 0 is
I. 4x² - 21x + 20 = 0
II. 8y² - 22y + 15 = 0
I. 99 x² + 31 x – 110 = 0
II. 6y² - 31y + 35 = 0
I. 2x2- 5x - 33 =0
II. 2y2+ 5y - 25 = 0
I. 2x2 – 19x + 45 = 0
II. y2 – 14y + 48 = 0
I. 14p2 – 135p + 81 = 0
II. 7q2 – 65q + 18 = 0
I. 18p²- 21p + 6 = 0
II. 16q² - 24q +9 = 0