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ATQ, Time taken to meet for the first time = 3600 ÷ (4 + 6) = 360 seconds So, time taken to meet for 10th time = 360 × 10 = 3600 seconds So, distance covered by 'A' in 3600 seconds = 3600 × 4 = 14400 metres And distance covered by 'B' in 3600 seconds = 3600 × 6 = 21600 metres So, required difference = 21600 - 14400 = 7200 metres
? + 156 ÷ 3 × 7 = 35% of 400 + (13)2
Find the simplified value of the given expression.
{12.75 × √64 + 13.5 × √(√256)} ÷ 6 + 49.5 ÷ 5.5
(√7225 x √1225)/(√625) = ?
The value of {5 − 5 ÷ (10 − 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:
(8.6 × 8.6 + 4.8 × 4.8 + 17.2 × 4.8) ÷ (8.62 – 4.82 ) = ? ÷ 19
390/? = √256 + 3.5
Find the simplified value of the given expression:
224 ÷ 4 + 7 X 36 - 8 of 15 + 162 - 300
2/5 of 3/4 of 7/9 of 7200 = ?
√? + √1296 + √729 = 464/4