The distance covered by a train in (4y-1) hours are (64y3-1) km. The speed of the train is.
a³-b³ = (a - b) (a² + ab + b²) The speed of the train =(64y3-1) /(4y-1) =(4y)3-1/ (4y-1) =(4y-1) (16y2+4y+1)/ (4y-1) = (16y² + 4y + 1) km/h The speed of the train is (16y² + 4y + 1) km/h.
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