In an 800-metre race, 'Neha' beats 'Tina' by '160' metres and 'Maya' by '240' metres. If 'Tina' and 'Maya' participate in a 500-metre race, and 'Maya' gets a head start of 50 metres, then find the distance between 'Tina' and 'Maya' when the winner reaches the finish line.
ATQ, Ratio of speeds of 'Neha', 'Tina', and 'Maya' = 800 : (800 - 160) : (800 - 240) = 10 : 8 : 7 So, ratio of speeds of Tina and Maya = 8 : 7 Distance covered by 'Maya' in the time taken by 'Tina' to cover 500 metres = 500 × (7/8) = 437.5 metres Total difference between 'Tina' and 'Maya' when 'Tina' reaches the finish line = 500 - (437.5 + 50) = 12.5 metres So, 'Tina' will beat 'Maya' by 12.5 metres.
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