Ratio of speeds of ‘A’ and ‘B’ is 6:11, respectively. If they participate in a 220-metre race and ‘B’ gives ‘A’, a head start of ‘m’ metres, then they finish the race at the same time. Find the value of ‘m’.
Let the distance covered by ‘A’ in the time ‘B’ covers 220 metres be ‘x’ metres (x/220) = (6/11) Or, x = 120 So, m = 220– 120 = 100 metres
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