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Let the speed of the train be x m/sec and the length of the train be y m, then According to the question x = (240 + y) / 10 ----(1) x = y / 6 ----(2) From equation (1) and equation (2) y / 6 = (240 + y) / 10 2y = 1400 + 6y 10y - 6y = 1440 y = 1440/4 =360m The length of the train is 360 m From equation (2) x = 360/6 x = 60 m/sec x = 60 x 18/5 x = 216 km/hr The speed of a train is 216 km/hr.
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