A person covers a certain distance at a certain speed. If he increases his speed by 40%, then he takes 15 minutes less to cover the same distance. Find the time taken by him to cover the distance when traveling at his original speed
Let the distance, original speed, and original time is taken be D km, S kmph, T hours, respectively.  Hence,  D = S × T D = (S × 1.4) × (T - 1/4) Thus, we can conclude, S × T = (S × 1.4) × (T - 1/4)  0.4T = 0.35  T = 0.875hours =52.5 minutes
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