A person walks at 5 km/h to reach the office on time. If the walking speed is increased to 6 km/h, the person will reach 10 minutes earlier. Find the time taken by the person to walk twice the distance at 8 km/h.
ATQ, Let the usual time taken by the person be 'T' hours. Using, distance = speed × time We have, 'D' = 5T ----------- (I) And, 'D' = 6 × {T - (10/60)} -------- (II) From equation (I) and (II), We have, 5T = 6 × {T - (10/60)} Or, 5T = 6T - 6 × (10/60) Or, T = 1 On putting the value of 'T' = 1 in equation (I), We have 'D' = 5 × 1 = 5 km So, the required time = (2 × 5) ÷ 8 = (10/8) = 1.25 hours
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