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ATQ, Usual speed of the cyclist = (240/6) = 40 km/h New speed of the cyclist = 0.25 × 40 = 10 km/h New time taken = (240/10) = 24 hours Alternate Solution: Let the usual speed of the cyclist be 10x km/hr. Therefore, decreased speed = 2.5x km/hr Since the distance covered is the same and time taken is inversely proportional to the speed: Ratio of time taken with usual speed to time taken with reduced speed = 6:24 = 1:4 Required time taken = 6 × (4/1) = 24 hours
? + 156 ÷ 3 × 7 = 35% of 400 + (13)2
Find the simplified value of the given expression.
{12.75 × √64 + 13.5 × √(√256)} ÷ 6 + 49.5 ÷ 5.5
(√7225 x √1225)/(√625) = ?
The value of {5 − 5 ÷ (10 − 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:
(8.6 × 8.6 + 4.8 × 4.8 + 17.2 × 4.8) ÷ (8.62 – 4.82 ) = ? ÷ 19
390/? = √256 + 3.5
Find the simplified value of the given expression:
224 ÷ 4 + 7 X 36 - 8 of 15 + 162 - 300
2/5 of 3/4 of 7/9 of 7200 = ?
√? + √1296 + √729 = 464/4