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    Question

    If a person walks at (2/3) of his normal speed, he arrives at his office 30 minutes late. What is the usual time taken by him to reach his office?

    A 50 min Correct Answer Incorrect Answer
    B 60 min Correct Answer Incorrect Answer
    C 45 min Correct Answer Incorrect Answer
    D 30 min Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the distance covered by the person to reach the office be 'd' meters, the usual time taken be 't' minutes, and the usual speed be 's' meters per minute. According to the question:

    3d=2s×(t+30)... (1) (d/s) = t So, d=s×t... (2) Using substitution from equation (2) into equation (1): 3st=2s×(t+30) Simplifying = 3st = 2st+60s Or, st=60s Thus, t = 60 Therefore, the usual time taken by the person to reach the office is 60 minutes.

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