A bus takes 6 hours to travel from city P to city Q. If the speed was reduced by 10% after covering 120 km, it takes 30 more minutes to complete the journey from city P to city Q. Determine the distance between city P and city Q.
ATQ,
Let the speed of bus be ‘x’ km/h. So, x × 6 = 120 + (9x/10) ×[6.5 – {120/x}] 6x = 120 + (9/10) × (6.5x – 120) 1.5x = 120 x = 80 Required distance = x × 6 = 480 km
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