ATQ,
Let the speed of bus be ‘x’ km/h. So, x × 6 = 120 + (9x/10) ×[6.5 – {120/x}] 6x = 120 + (9/10) × (6.5x – 120) 1.5x = 120 x = 80 Required distance = x × 6 = 480 km
62, 79, 98, 119, 142, 165
79, 152, 231, 314, 405, 500
128, 128, 64, 192, 42 , 240
15, 30, 30, 20, 10, 8
72, 36, 54, 135, 470.5, 2126.25
21, 23, 27, 35, 51, 87
18 45 90 235 450 1125 2250
...2, 6, 24, 96, 384, 1536, 6144
53, 57, 66, 82, 117, 143, 192
16, 36, 128, 768, 6144, 61440
