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Let the total distance covered by ‘A’ be ‘4x’ km Distance covered with speed of 15 km/hr = 0.5 × 4x = 2x km/hr Distance covered with speed of 5 km/hr = 0.5 × (4x – 2x) = ‘x’ km/hr ATQ, (2x/15) + (x/5) + (x/3) = 10 Or, {(2x + 3x + 5x)/15} = 10 Or, 10x = 150 Or, x = 150/10 = 15 Therefore, total distance covered by ‘A’ = 4x = 60 km
5, 5, 15, 75, ?, 4725
8, 24, 48, 80, ?, 168
8 13 36 123 ? 2585
250, 279, 311, 349, 396, ?
840, 2520, 630, 3150, ?, 3675
12, 24, 46, 78, 120, ?
81, 41, 42, 64.5, ?, 330
8, 58, 75, 94, 115, ?
200 ? 96 38.4 7.68 0