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Start learning 50% faster. Sign in nowSuppose the speeds of the two trains x m/sec and 3x m/sec respectively. Also, suppose that the lengths of the two trains are A m and B m respectively. Then, ((A+B)/(3x - x)) = 50 ……………….. (i) and (A/(3x - x)) = 20 ……………… (ii) Dividing (i) by (ii), we get ((A+B)/A) = 50/20 B/A + 1 = 5/2 B/A = 3/2 or A:B = 2:3
(320 + 342 + 530 + 915) ÷ (20 + 22 – x + 18) = 43, then the value of x is:
√4096 + √3249 = (?)2
What will come in the place of question mark (?) in the given expression?
√49 + √144% of 3600 = ?
36% of 250 + 26 ÷ 2 × ? = 207
8 × 9 + ? – 6 × 11 = 12 × 8
√( (664+ √(136+ √(59+ √(21+ √(7+ √81) ) ) ) ) ) = ?
(√ 196 x √ 36 x √ 100) = ?% of 200