Abhinav improved his average travel speed by 8 km/h after journeying for 5 hours, completing his trip in a total of 8 hours. If instead he had boosted his speed by 18 km/h after the initial 5 hours, he would have arrived at his destination 30 minutes earlier. Calculate the distance Abhinav covered during the portion of his trip with the increased speed.
Let, the distance travelled by after 5 hours = ‘y’ km So, y/ (7.5 – 5) – y/ (8 – 5) = 18 – 8 y/2.5 – y/3 = 10 0.5y = 75 y = 150 So, distance travelled by Abhinav after travelling for five hours = 150 km
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