Chetak and Badal are two horses starting simultaneously from points 'D' and 'E' respectively and run toward each other. Chetak gallops at a speed of 60 km/hr, while Badal runs at a speed that is 25% slower than Chetak's. By the time they meet, Chetak has traveled 600 km more than Badal. What is the total distance between points 'D' and 'E'?
Let 't' be number of hours after which they met each other. Speed of Badal = 60 X 0.75 = 45 km/hr ATQ, 60t - 45t = 600 So, 't' = (600/15) = 40 Therefore, total distance between points 'D' and 'E' : = (60t + 45t) = 105t = 105 X 40 = 4200 km
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