Question
Two trains depart from the same station. The first train
departs at 8:00 A.M., traveling at a speed of 60 km/h. Two hours later, at 10:00 A.M., the second train leaves the station, traveling at a faster speed of 72 km/h. At what time will the second train catch up to the first train?Solution
We can see that the first train leaves 2 hours before the second train. So, distance travelled in 2 hours by the first train = 2 X 60 = 120 km So, time taken by the two trains to meet = 120 Ă· (72 - 60) = 10 hours So, the second train will meet the first train at 10:00 AM + 10 hours = 8:00 P.M.
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II. Partial efficiency measure
III. Specific efficiency measure
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