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ATQ, Let speed of 'Arjun' and 'Bishu' be '2a' m/s and 'a' m/s, respectively And, let they meet after 't' seconds. So, 2a × t + a × t = 1200 Or, t = (1200/3x) = (400/a) Required distance = distance travelled by 'Bishnu' in 't' seconds = (400/a) × a = 400 metres Alternate solution Ratio of speeds of 'Arjuna' and 'Bishnu' = 2:1 Since, time is constant. So, ratio of distance travelled by 'Arjuna' and 'Bishnu' = 2:1 So, required distance = 1200 × (1/3) = 400 metres
1000÷ 250 = ( 3√? × √1444) ÷ ( 3√512 × √361)
1540 ÷ 7 - 184 ÷ 8 = ?
12.232 + 29.98% of 539.99 = ? × 5.99
√256 * 3 – 15% of 300 + ? = 150% of 160
18 × 15 + 86 – 58 =? + 38
[5 X {(52 X 5) - 10} + 50 of 20] = ?
4(1/3) × 2(11/14) = 50% of ? + 86/11
(15 x 6 + 60% of 500 - 16 x 7) = ?
25% of 140 + 2 × 8 = ? + 9 × 5
If a nine-digit number 389x6378y is divisible by 72, then the value of √(6x + 7y) will be∶