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ATQ, Let speed of 'Arjun' and 'Bishu' be '2a' m/s and 'a' m/s, respectively And, let they meet after 't' seconds. So, 2a × t + a × t = 1200 Or, t = (1200/3x) = (400/a) Required distance = distance travelled by 'Bishnu' in 't' seconds = (400/a) × a = 400 metres Alternate solution Ratio of speeds of 'Arjuna' and 'Bishnu' = 2:1 Since, time is constant. So, ratio of distance travelled by 'Arjuna' and 'Bishnu' = 2:1 So, required distance = 1200 × (1/3) = 400 metres
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