Let the distance travelled by bus be 'D' km and usual time taken by bus to reach school be 'T' hours. So, 'D' = 50T -------- (I) And, 'D' = 40 x [T + (18/60) ] Or, 'D' = 40T + 12 -------- (II) From equation I and II, we get, 50T = 40T + 12 Or, 10T = 12 So, 'T' = (12/10) = 1.2 Therefore, required distance = 50T = 50 x 1.2 = 60 km
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