Question
Pratham is traveling from Delhi to Banthara, a distance
of 382 km. She starts her journey from Delhi at a speed of 120 km/h, and her speed decreases by 10 km/h every 30 minutes. If she begins her journey at 8:45 AM, determine the time at which Pratham reaches Banthara.Solution
Distance travelled by Pratham in first 30 minutes = 120 x 1/2 = 60 km Distance travelled by Pratham in next 30 minutes = 110 x 1/2 = 55 km Now we have to take the value which is nearest to 380 km. So, in 5 hours distance travelled = 60 + 55…….. + 15 = 10/2 x (60 + 15) = 375 km Time taken to travel rest 7 km = 7/20 x 60 = 21 minutes Total time taken = 5 hours + (21) minutes = 5 hours 21 minutes So required time = 8:45 am + 5 hours + 21 minutes = 2:06 pm Hence answer is option B
- The sum of two numbers is 90 whereas the sum of their reciprocals is (30/11). Find the square of the product of the two numbers.
Sandeep can solve 20 questions in 1 hour. If he decreased his efficiency by 20%, then how much time would he take to solve the same number of questions?
If (3/4)th of a number is subtracted from (5/6)th of that number, then the resultant will be (2/6). Find the number.
The ratio between two numbers is 2:3 and the sum of their squares is 2197. The numbers are:
Find the largest number that, when dividing 259, 323, and 640, leaves remainders of 4, 8, and 10, respectively.
The value of √(56+√(56 +√(56+ √(56+√56+ ................ )) )) is
- If 519x238y is divisible by 72, then find (2x - 4y).
The sum of any seven consecutive natural numbers is always divisible by which of the following numbers?
- A number gives a remainder of 19 when divided by 50. Find the remainder when the same number is divided by 25.
Find the sum of the first 50 natural numbers.