Question
In a 20 km race, A, B, and C are running at constant
speeds. If A finishes the race 4 km ahead of B, and B finishes 4 km ahead of C, by how many meters does A beat C?Solution
When ‘A’ covers 20 km, ‘B’ will cover 16 km Similarly, when ‘B’ covers 20 km, ‘C’ covers 16 km Therefore, when ‘B’ covers 16 km, then ‘C’ will cover = (16 × 16)/20 = 12.8 km Therefore, ‘A’ will beat ‘C’ by = 20 – 12.8 = 7.2 km
Consider the following pairs:
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