Question
Car A departs from Varanasi towards Lucknow at 8:00 AM,
traveling at a speed of 48 km/h. Car B starts from Lucknow towards Varanasi at 9:15 AM, with a speed that is 25% greater than Car A's speed. If the distance between Varanasi and Lucknow is 1140 km, at what distance from Varanasi will the two cars meet?Solution
Speed of cars A = 48 kmph Speed of cars B = 48 * 125/100 = 60 kmph After one hour and 15 minutes cars A covers the distance = 48 + 48/4 = 60 km Time taken by two cars meet each other = (1140 – 60)/(60 + 48) = 10 hours Required distance = 10 * 48 + 60 = 480 + 60 = 540 km
More Time and distance Questions
40.5 ÷ [4/5 of (32 + 18) - 29/2] = ? ÷ 102
(1/2) – (3/5) + 3(1/3) = ? + (5/6)
(350/?) = 23 + 33
25% of 250 + 32% of 200 = ? ÷ √ 16
? = 20% of 1200 + 256
21% of 400 − 150 = ? − 77
172 - 92 + 121 - 74 = ?
24% of 150% of 500 + 140 = ? × 8
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
? = 65% of 40% of (20 × 250) − 200
