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Let the speed of the train be x m/s, and the length of the train be y m. When it crosses a man Distance = speed × time taken Y = 12x Now when it crosses the platform (y+480) = 36x From these two equations Y = 240 m, and x = 20m/s Now when it crosses the bike Speed of bike = 27×5/18 = 15/2 m/s Now 240 = (20-15/2) × time Time = 240×2/25 Time = 19.2 s
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