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Let the speed of the man be ‘x’ km/hrTherefore, speed of the bus = 2.5x km/hrTotal time taken = 2 hours 3 minutes = 2 hours + (3/60) hours = 2.05 hoursAccording to the question,(40/2.5x) + (25/x) = 2.05Or, (40 + 62.5) = 2.05 × 2.5xOr, 5.125x = 102.5Or, x = 20Therefore, speed of the bus = 2.5x = 50 km/hr
I. 3p² - 14p + 15 = 0
II. 15q² - 34q + 15 = 0
I. 2x2 – 10x – 48 = 0
II. y2 – 16y – 297 = 0
I. x² – 44x + 468 = 0
II. y² – 30y + 216 = 0
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0
I. 5x² - 28x + 39 = 0
II. 2y² - 13y + 20 = 0
I. x2 - 5x - 14 = 0
II. y2 - 16y + 64 = 0
(i) 2x² + 14x - 16 = 0
(ii) y² – y – 12 = 0
I. 3x6- 19x3+16=0
II. 9y4- 27y2+20=0
I. 5x + 2y = 31
II. 3x + 7y = 36
Equation 1: x² - 50x + 500 = 0
Equation 2: y² - 60y + 600 = 0