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Let the speed of Renu and Meenu be 4x km/hr and 5x km/hr respectively.
ATQ,
5x - 4x = x = 4
Speed of Renu = 16 km/hr
Speed of Meenu = 20 kmhr
Distance covered by Renu in 1.5 hours (9:00 AM to 10:30 AM) = 1.5 X 16 = 24 km
Remaining distance = 300 - 24 = 276 km
Time in which both will meet = {276 ÷ (16 + 20) }= 7 hours 40 minutes
Therefore, required time = 10:30 + 7:40 = 18:10 = 6:10 PM
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