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ATQ,
Sum of the distance travelled by both cars = 750 km
Let the speed of car Y = ‘x’ km/h
So, speed of car X = ‘x + 10’ km/h
So, 6x + 6(x + 10) = 750
Or, 6x + 6x + 60 = 750
Or, 12x = 690
Or, x = 57.5
So, the speed of car X = (x + 10) = (57.5 + 10) = 67.5 km/h
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