Question
A bus was travelling from Jaipur to Udaipur was delayed
by 15 minutes and made up for the delay on a section of 85 km travelling with a speed 12 km per hour higher than its normal speed. Find the approximate original speed of the bus?Solution
Let original speed = 'x' km/hr. Time to cover 85 km at normal speed = 85/x . Time to cover 85 km at increased speed (x+12) = 85/(x+12) Time difference = 15 minutes = 1/4 hours 
Simplify and solve: 
Solve quadratic equation: Using the quadratic formula, x = 58.15  x = 58.15 km/hr.
Statements: B > C = D > H ≥ A; B ≤ D = F ≤ E < G
Conclusions:
I. H < E
II. B ≤ E
...Which of the following is true in the given expression?
 G < H ≤ I, V ≥ W = G, R ≤ I = A
In the question, relationship between some elements is shown in the statements (s). These statements are followed by two conclusions. Read the stateme...
Statements: Q ≤ B = S < U > M ≥ Z
Conclusion: I. U > Q II. S ≤ Z
...Statements: R = S ≥ T, U < Q < W = T, U = Z > V
Conclusions:
I. R > U
II. S ≥ Z
 III. V < T
Statements:
A ≤ B < C > K; C < S > T; T < U < V
Conclusions:
I). Â A < S
II).  A ≥ S
...Statement: H > G = M > S; GÂ `>=` Â T > L; MÂ `<=` Â F <Â Â U
Conclusion: Â I. F > SÂ Â Â Â Â Â Â Â Â Â Â II. T < H
...- Statements: P > Q ≥ R < S; T ≤ R > U ≥ V
Conclusions:
I. S > V
II. U < P
III. Q > T Which of the following symbols should be placed in the blank spaces respectively (in the same order from left to right) in order to complete the given e...
Statements: S > U ≥ V = X, Y < M < X, Y = T ≥ W
Conclusions:
I. S > Y
II. M ≤ U
III. W < X
