A carriage travels in the fog passed along a man who was walking @ 3kmph in the same direction. He could see the carriage for 4 minutes and it was visible to him upto a distance of 100 metres. What was the speed of carriage?
60 min = 3,000 4 min = 3000/60 × 4 ⇒ 200 Carriage ⇒ 4 min = 300 60 min = 300/4 × 60 ⇒ 4500 Speed = 4.5kmph Alternate Method: (d₁)/(d₂) = (S₁)/(S₂) 300/200 = (S₁)/3 ⇒ S₁ ⇒ 9/2 = 4.5kmph
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