A bus travels point P at 6:30 am and reaches point Q at 11:30 am. Another train leaves point Q at 8:30 am and reaches point P at 11 am. At what time would the two buses meet?
Let the distance be D km Speed of the 1st bus = D/5 km/hr Speed of the 2nd bus = (2 D)/5 km/hr Speed of 2nd bus = 2 × speed of 1st bus ∴ Distance travelled by 1st bus till 8:30 am = 2 × D/5 = (2 D)/5 Now, Distance between buses = D - (2 D)/5 = (3 D)/5 km Time taken = ((3 D)/5)/( D/5 + (2 D)/5 ) = 1 hour ∴ 8:30 am + 1 hour = 9:30 am
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