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Since Team A is taking less time than Team B and each member has the same efficiency. With this we can say that the strength of Team A will be greater than that of Team B. Thus only (i) and (iii) satisfy the condition (first term is greater than that of second term). Alternative Method: Team A Team B Time: T T+6 Strength: A B Work Done: AT = B(T+6) ؞ Then, AT = B(T+6) A/B = (T+6)/T Thus, we can say that A > B. Hence only option (i) and (iii) satisfy the condition.
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