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Since Team A is taking less time than Team B and each member has the same efficiency. With this we can say that the strength of Team A will be greater than that of Team B. Thus only (i) and (iii) satisfy the condition (first term is greater than that of second term). Alternative Method: Team A Team B Time: T T+6 Strength: A B Work Done: AT = B(T+6) ؞ Then, AT = B(T+6) A/B = (T+6)/T Thus, we can say that A > B. Hence only option (i) and (iii) satisfy the condition.
I. 63x² + 37 x – 40 = 0
II. 15 y² + 29 y + 12 = 0
I. 15y2+ 4y – 4 = 0
II. 15x2+ x – 6 = 0
I. 2x² - 15x + 13 = 0
II. 3y² - 6y + 3 = 0
Equation 1: x² - 220x + 12100 = 0
Equation 2: y² - 210y + 11025 = 0
l). p² - 29p + 204 = 0
ll). q² + 4q - 221 = 0
Equation 1: x² - 144x + 5184 = 0
Equation 2: y² - 130y + 4225 = 0
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
I. 2y² - 11 y + 15 = 0
II. 2x² + 3x – 14 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...