Question
Ram, Ankit and Shivam together can do a piece of work in
10/3 days. Ram could do it alone in 6 days and Ankit could do it alone in 12days. In how many days could Shivam do it alone?Solution
Shivam's 1 day work = 3/10 - (1/6+ 1/12) = 1/20 So Shivam will do this job in 20 days Alternate Method: R+A+S R A 10/3 6 12 LCM = 60 units Eff 18 : 10 : 5 So eff of S = 18 - (10+5) = 3 units So Shivam can do whole job in = 60/3 = 20 days
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