A, B and C can complete a work in 10, 20 and 15 days respectively. A left the work 3 days before the work was completed and B left 1 days after A had left. The number of days required to complete the whole work is:
A’s one day work = 1/10 B’s one day work = 1/20 C’s one day work = 1/15 Let total units of work be = 60 Efficiency of (A) = 6 Efficiency of (B) = 3 Efficiency of (C) = 4 Let ‘x’ days are required to complete the whole work. => 4x + 6(x-3) + 3(x-2) = 60 => 4x + 6x – 18 + 3x – 6 = 60 => 13x = 84 => x = 84/13 days
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0
