P and Q can separately finish the work in 15 days and 25 days respectively. They worked together and P left the work, so Q complete the remaining work in 5 days. After how many days P left the work?
P can do a work in 15 days. Q can do a work in 25 days. Let P left after x days. Q worked for (x+5) days. ∴ 1/15 × x + 1/25 (x+5) = 1 x/15 + x/25 + 1/5 = 1 (5x+3x)/75 = 4/5 8x/75 = 4/5 x = 15/2 days Alternate method: Let total work = LCM(15, 25) = 75 So P’s 1 day work = 5 & Q’s 1 day work =3 So Q’s 5 days work in last = 3×5 = 15 So remaining work = 75 – 15 = 60 So this 60 units of work is completed by both in = 60/(5+3) = 60/8 =7.5 days
120.02% of 599.90 + (34.78/20.89) × (47.98) = ?2 – 10.022
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
? = (5.8)2 + (8.9)2 + (4.7) 2 + 24.7% of 20
(5.013 – 20.04) = ? + 9.98% of 6199.98
?% of (144.31 ÷ 17.97 × 60.011) = 239.98
39.9% of 1720 + 80.2% of 630 = 89.9% of 1280 + ?
45.22% of (71.9 x 5.01) + 69.97 =?
? = 54.89 × 270.08 ÷ 135.17 + 464.35 ÷ 29.03
?% of 549.83 – 18.05 × 31.96 = 44.94% of 479.84 – 13.98 × 33.13
