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Total work = Number of days×1 day’s work (efficiency) Total work = LCM (12, 16) = 48 unit 1 day’s work of A = 48/12 = 4 unit 1 day’s work of B = 48/16 = 3 unit 1 day’s work of (A + B) = 4 + 3 = 7 unit Now, 3 day’s work of (A + B) together = 3× 7 = 21 unit Remaining work = 48 – 21 = 27 Remaining work completed by B = 27/3 = 9 days
Select an appropriate figure from the four options that will come in the place of question mark (?) and complete the figure.
Which figure should replace the question mark (?) if the series were to continue?
In each of the following questions, find out which of the answer figures can be formed from the pieces given in the problem figure.
Select an appropriate figure from the four options that would complete the figure.