A and B together can do a work in 12 days. If A can alone do the same work in 18 days, then in how many days B alone will do the same work?
Total work = Number of days×1 day’s work (efficiency) Total work = LCM (12, 18) = 36 unit 1 day’s work of (A+B) = 36/12 = 3 unit 1 day’s work of A = 36/18 = 2 unit 1 day’s work of B = 3 - 2 = 1 unit Now, Time taken by B to completed the work = 36/1 = 36 days
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