A and B together can do a work in 8 days. If A can alone do the same work in 12 days, then in how many days B alone will do the same work?
Total work = Number of days×1 day’s work (efficiency) Total work = LCM (8, 12) = 24 unit 1 day’s work of (A+B) = 24/8 = 3 unit 1 day’s work of A = 24/12 = 2 unit 1 day’s work of B = 3 - 2 = 1 unit Now, Time taken by B to completed the work = 24/1 = 24 days
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