A takes 32 days to complete a work while B can complete the same work in 12 days less than A. If C can complete 25% of the work in 12 days, then find the time taken by A, B and C together to complete 61.25% of the work.
Time taken by A to complete the work = 32 days Time taken by B to complete to the work = 32 – 12 = 20 days Time taken by C to complete the work = 12/0.25 = 48 days Let the total work = 480 units Efficiency of A = 480/32 = 15 units/day Efficiency of B = 480/20 = 24 units/day Efficiency of C = 480/48 = 10 units/day Therefore, 1 days work of (A + B + C) = 15 + 24 + 10 = 49 units Therefore, required time taken = 0.6125 × 480/49 = 6 days
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