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Let the total work be 16 units. (LCM of 8 and 16) Efficiency of A = 16/8 = 2 units/day Efficiency of B = (16/16) × (40/100) = 2/5 units/day Ratio of the efficiency of A : B = 2 : 2/5 = 10:2 Share of A = (10/12) × 1500 = Rs.1250
If sinAo = (√3/2), then find the value of (sin245o + cos230o) × A ÷ 5 given that 0 < A < 90...
If {(tanx)/(secx)} × cosx = (1/2), then determine the value of ‘sin2x’.
If cos θ + sec θ = √2, then the value of cos³ θ+ sec³ θ is:
If tan 4θ = cot 14θ, then find the value of cos 9θ.
Find the value of sin(θ) if 2sinθ = tanθ, for 0 < θ < 90°.