P alone can finish a piece of work ‘M’ in 6 days while Q takes 3 days to finish it alone. P, Q and R working together can finish the work ‘N’ which is 10 times of work ‘M’ in 4 days. How long will R take to finish work ‘N’, when working alone? Let the work ‘M’ = 6 units (LCM of 6 and 3)
Efficiency of P = 6/6 = 1 units Efficiency of Q = 6/3 = 2 units Efficiency of P, Q and R = (6 × 10)/4 = 15 units per day Efficiency of R = 15 – (1 + 2) = 12 units per day Time taken by R to finish work ‘N’ = 60/12 = 5 days
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0