A alone can complete 60% of a work in 36 days while B takes 30 days more than A to complete it. If B and C together can complete the work in 40 days, then find the time taken by C alone to complete the same work.
Time taken by A alone to complete the entire work = 36/0.6 = 30 days Time taken by B alone to complete the entire work = 30 + 30 = 60 days Let the total work = L.C.M of 60, 90 and 40 = 360 units Then, efficiency of B = (360/90) = 4 units/day Combined efficiency of B and C = (360/40) = 9 units/day So, efficiency of C alone = 9 – 4 = 5 units/day So, time taken by C alone to complete the entire work = (360/5) = 72 days
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