P and Q can complete a work in 20 days and 30 days, respectively. P, Q and R together can complete the work in 10 days. If R get a total wage of Rs. 4800 to complete the work alone, then find the per day wage of R.
Let the total work be LCM of (20, 30 and 10) = 60 units Number of units of work done by P alone in one day = 60/20 = 3 units Number of units of work done by Q alone in one day = 60/30 = 2 units Number of units of work done by P, Q and R together in one day = 60/10 = 6 units Number of units of work done by R alone in one day = 6 – 3 – 2 = 1 unit So, time taken by R alone to complete the work = 60/1 = 60 days So, per day wage of R = 4800/60 = Rs. 80
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