Akhil and Nikhil together can complete a work in 10 days while Nikhil alone takes 15 days to complete 30% of the work. If the efficiency of Sachin is 25% more than that of Akhil, then find the time taken by Sachin alone to complete the whole work.
Time taken by Nikhil to complete the whole work alone = 15/0.30 = 50 days Let the total work = 50 units Efficiency of (Akhil + Nikhil) = 50/10 = 5 units/day Efficiency of Nikhil = 50/50 = 1 units/day Efficiency of Akhil = 5 - 1 = 4 units/day Therefore efficiency of Sachin = 1.25 x 4 = 5 units/day Time taken by Sachin to complete the whole work alone = 50/5 = 10 days
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0
